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x^2+5x=18.75
We move all terms to the left:
x^2+5x-(18.75)=0
We add all the numbers together, and all the variables
x^2+5x-18.75=0
a = 1; b = 5; c = -18.75;
Δ = b2-4ac
Δ = 52-4·1·(-18.75)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-10}{2*1}=\frac{-15}{2} =-7+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+10}{2*1}=\frac{5}{2} =2+1/2 $
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